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(2/3)x^2=4/5
We move all terms to the left:
(2/3)x^2-(4/5)=0
Domain of the equation: 3)x^2!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x^2-(+4/5)=0
We get rid of parentheses
(+2/3)x^2-4/5=0
We calculate fractions
()/3x^2*5)+(-12x)/3x^2*5)=0
We calculate fractions
We do not support expression: x^6
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